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Let P be the plane, which contains the line of intersection of the planes, `x+y+z-6=0`

Let P be the plane, which contains the line of intersection of the planes, `x+y+z-6=0` Let P be the plane, which contains the line of intersection of the planes, `x+y+z-6=0` and `2x+3y+z+5=0` and it is perpendicular to the XY-plane. Then, the distance of the point (0, 0, 256) from P is equal to

`x+y+z-6=0`

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